Integrand size = 23, antiderivative size = 85 \[ \int \frac {\tan ^2(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^2} \, dx=-\frac {x}{a^2}+\frac {(a+2 b) \arctan \left (\frac {\sqrt {b} \tan (e+f x)}{\sqrt {a+b}}\right )}{2 a^2 \sqrt {b} \sqrt {a+b} f}+\frac {\tan (e+f x)}{2 a f \left (a+b+b \tan ^2(e+f x)\right )} \]
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Time = 0.17 (sec) , antiderivative size = 85, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.261, Rules used = {4226, 2000, 482, 536, 209, 211} \[ \int \frac {\tan ^2(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^2} \, dx=\frac {(a+2 b) \arctan \left (\frac {\sqrt {b} \tan (e+f x)}{\sqrt {a+b}}\right )}{2 a^2 \sqrt {b} f \sqrt {a+b}}-\frac {x}{a^2}+\frac {\tan (e+f x)}{2 a f \left (a+b \tan ^2(e+f x)+b\right )} \]
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Rule 209
Rule 211
Rule 482
Rule 536
Rule 2000
Rule 4226
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {x^2}{\left (1+x^2\right ) \left (a+b \left (1+x^2\right )\right )^2} \, dx,x,\tan (e+f x)\right )}{f} \\ & = \frac {\text {Subst}\left (\int \frac {x^2}{\left (1+x^2\right ) \left (a+b+b x^2\right )^2} \, dx,x,\tan (e+f x)\right )}{f} \\ & = \frac {\tan (e+f x)}{2 a f \left (a+b+b \tan ^2(e+f x)\right )}-\frac {\text {Subst}\left (\int \frac {1-x^2}{\left (1+x^2\right ) \left (a+b+b x^2\right )} \, dx,x,\tan (e+f x)\right )}{2 a f} \\ & = \frac {\tan (e+f x)}{2 a f \left (a+b+b \tan ^2(e+f x)\right )}-\frac {\text {Subst}\left (\int \frac {1}{1+x^2} \, dx,x,\tan (e+f x)\right )}{a^2 f}+\frac {(a+2 b) \text {Subst}\left (\int \frac {1}{a+b+b x^2} \, dx,x,\tan (e+f x)\right )}{2 a^2 f} \\ & = -\frac {x}{a^2}+\frac {(a+2 b) \arctan \left (\frac {\sqrt {b} \tan (e+f x)}{\sqrt {a+b}}\right )}{2 a^2 \sqrt {b} \sqrt {a+b} f}+\frac {\tan (e+f x)}{2 a f \left (a+b+b \tan ^2(e+f x)\right )} \\ \end{align*}
Result contains complex when optimal does not.
Time = 8.55 (sec) , antiderivative size = 346, normalized size of antiderivative = 4.07 \[ \int \frac {\tan ^2(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^2} \, dx=\frac {(a+2 b+a \cos (2 (e+f x)))^2 \sec ^4(e+f x) \left (-\frac {16 x+\frac {\left (-a^3+6 a^2 b+24 a b^2+16 b^3\right ) \arctan \left (\frac {\sec (f x) (\cos (2 e)-i \sin (2 e)) (-((a+2 b) \sin (f x))+a \sin (2 e+f x))}{2 \sqrt {a+b} \sqrt {b (\cos (e)-i \sin (e))^4}}\right ) (\cos (2 e)-i \sin (2 e))}{b (a+b)^{3/2} f \sqrt {b (\cos (e)-i \sin (e))^4}}+\frac {\left (a^2+8 a b+8 b^2\right ) ((a+2 b) \sin (2 e)-a \sin (2 f x))}{b (a+b) f (a+2 b+a \cos (2 (e+f x))) (\cos (e)-\sin (e)) (\cos (e)+\sin (e))}}{a^2}+\frac {\frac {(a+2 b) \arctan \left (\frac {\sqrt {b} \tan (e+f x)}{\sqrt {a+b}}\right )}{(a+b)^{3/2}}-\frac {a \sqrt {b} \sin (2 (e+f x))}{(a+b) (a+2 b+a \cos (2 (e+f x)))}}{b^{3/2} f}\right )}{64 \left (a+b \sec ^2(e+f x)\right )^2} \]
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Time = 2.40 (sec) , antiderivative size = 77, normalized size of antiderivative = 0.91
method | result | size |
derivativedivides | \(\frac {\frac {\frac {a \tan \left (f x +e \right )}{2 a +2 b +2 b \tan \left (f x +e \right )^{2}}+\frac {\left (a +2 b \right ) \arctan \left (\frac {b \tan \left (f x +e \right )}{\sqrt {\left (a +b \right ) b}}\right )}{2 \sqrt {\left (a +b \right ) b}}}{a^{2}}-\frac {\arctan \left (\tan \left (f x +e \right )\right )}{a^{2}}}{f}\) | \(77\) |
default | \(\frac {\frac {\frac {a \tan \left (f x +e \right )}{2 a +2 b +2 b \tan \left (f x +e \right )^{2}}+\frac {\left (a +2 b \right ) \arctan \left (\frac {b \tan \left (f x +e \right )}{\sqrt {\left (a +b \right ) b}}\right )}{2 \sqrt {\left (a +b \right ) b}}}{a^{2}}-\frac {\arctan \left (\tan \left (f x +e \right )\right )}{a^{2}}}{f}\) | \(77\) |
risch | \(-\frac {x}{a^{2}}+\frac {i \left (a \,{\mathrm e}^{2 i \left (f x +e \right )}+2 b \,{\mathrm e}^{2 i \left (f x +e \right )}+a \right )}{a^{2} f \left (a \,{\mathrm e}^{4 i \left (f x +e \right )}+2 a \,{\mathrm e}^{2 i \left (f x +e \right )}+4 b \,{\mathrm e}^{2 i \left (f x +e \right )}+a \right )}+\frac {\ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+\frac {-2 i b a -2 i b^{2}+a \sqrt {-a b -b^{2}}+2 b \sqrt {-a b -b^{2}}}{a \sqrt {-a b -b^{2}}}\right )}{4 \sqrt {-a b -b^{2}}\, f a}+\frac {\ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+\frac {-2 i b a -2 i b^{2}+a \sqrt {-a b -b^{2}}+2 b \sqrt {-a b -b^{2}}}{a \sqrt {-a b -b^{2}}}\right ) b}{2 \sqrt {-a b -b^{2}}\, f \,a^{2}}-\frac {\ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+\frac {2 i b a +2 i b^{2}+a \sqrt {-a b -b^{2}}+2 b \sqrt {-a b -b^{2}}}{a \sqrt {-a b -b^{2}}}\right )}{4 \sqrt {-a b -b^{2}}\, f a}-\frac {\ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+\frac {2 i b a +2 i b^{2}+a \sqrt {-a b -b^{2}}+2 b \sqrt {-a b -b^{2}}}{a \sqrt {-a b -b^{2}}}\right ) b}{2 \sqrt {-a b -b^{2}}\, f \,a^{2}}\) | \(435\) |
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Leaf count of result is larger than twice the leaf count of optimal. 189 vs. \(2 (73) = 146\).
Time = 0.30 (sec) , antiderivative size = 458, normalized size of antiderivative = 5.39 \[ \int \frac {\tan ^2(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^2} \, dx=\left [-\frac {8 \, {\left (a^{2} b + a b^{2}\right )} f x \cos \left (f x + e\right )^{2} + 8 \, {\left (a b^{2} + b^{3}\right )} f x - 4 \, {\left (a^{2} b + a b^{2}\right )} \cos \left (f x + e\right ) \sin \left (f x + e\right ) + {\left ({\left (a^{2} + 2 \, a b\right )} \cos \left (f x + e\right )^{2} + a b + 2 \, b^{2}\right )} \sqrt {-a b - b^{2}} \log \left (\frac {{\left (a^{2} + 8 \, a b + 8 \, b^{2}\right )} \cos \left (f x + e\right )^{4} - 2 \, {\left (3 \, a b + 4 \, b^{2}\right )} \cos \left (f x + e\right )^{2} + 4 \, {\left ({\left (a + 2 \, b\right )} \cos \left (f x + e\right )^{3} - b \cos \left (f x + e\right )\right )} \sqrt {-a b - b^{2}} \sin \left (f x + e\right ) + b^{2}}{a^{2} \cos \left (f x + e\right )^{4} + 2 \, a b \cos \left (f x + e\right )^{2} + b^{2}}\right )}{8 \, {\left ({\left (a^{4} b + a^{3} b^{2}\right )} f \cos \left (f x + e\right )^{2} + {\left (a^{3} b^{2} + a^{2} b^{3}\right )} f\right )}}, -\frac {4 \, {\left (a^{2} b + a b^{2}\right )} f x \cos \left (f x + e\right )^{2} + 4 \, {\left (a b^{2} + b^{3}\right )} f x - 2 \, {\left (a^{2} b + a b^{2}\right )} \cos \left (f x + e\right ) \sin \left (f x + e\right ) + {\left ({\left (a^{2} + 2 \, a b\right )} \cos \left (f x + e\right )^{2} + a b + 2 \, b^{2}\right )} \sqrt {a b + b^{2}} \arctan \left (\frac {{\left (a + 2 \, b\right )} \cos \left (f x + e\right )^{2} - b}{2 \, \sqrt {a b + b^{2}} \cos \left (f x + e\right ) \sin \left (f x + e\right )}\right )}{4 \, {\left ({\left (a^{4} b + a^{3} b^{2}\right )} f \cos \left (f x + e\right )^{2} + {\left (a^{3} b^{2} + a^{2} b^{3}\right )} f\right )}}\right ] \]
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\[ \int \frac {\tan ^2(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^2} \, dx=\int \frac {\tan ^{2}{\left (e + f x \right )}}{\left (a + b \sec ^{2}{\left (e + f x \right )}\right )^{2}}\, dx \]
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Time = 0.27 (sec) , antiderivative size = 75, normalized size of antiderivative = 0.88 \[ \int \frac {\tan ^2(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^2} \, dx=\frac {\frac {\tan \left (f x + e\right )}{a b \tan \left (f x + e\right )^{2} + a^{2} + a b} + \frac {{\left (a + 2 \, b\right )} \arctan \left (\frac {b \tan \left (f x + e\right )}{\sqrt {{\left (a + b\right )} b}}\right )}{\sqrt {{\left (a + b\right )} b} a^{2}} - \frac {2 \, {\left (f x + e\right )}}{a^{2}}}{2 \, f} \]
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Time = 0.55 (sec) , antiderivative size = 94, normalized size of antiderivative = 1.11 \[ \int \frac {\tan ^2(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^2} \, dx=\frac {\frac {{\left (\pi \left \lfloor \frac {f x + e}{\pi } + \frac {1}{2} \right \rfloor \mathrm {sgn}\left (b\right ) + \arctan \left (\frac {b \tan \left (f x + e\right )}{\sqrt {a b + b^{2}}}\right )\right )} {\left (a + 2 \, b\right )}}{\sqrt {a b + b^{2}} a^{2}} - \frac {2 \, {\left (f x + e\right )}}{a^{2}} + \frac {\tan \left (f x + e\right )}{{\left (b \tan \left (f x + e\right )^{2} + a + b\right )} a}}{2 \, f} \]
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Time = 20.67 (sec) , antiderivative size = 711, normalized size of antiderivative = 8.36 \[ \int \frac {\tan ^2(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^2} \, dx=\frac {\mathrm {tan}\left (e+f\,x\right )}{2\,a\,f\,\left (b\,{\mathrm {tan}\left (e+f\,x\right )}^2+a+b\right )}-\frac {x}{a^2}-\frac {\mathrm {atan}\left (\frac {\frac {\left (\frac {\mathrm {tan}\left (e+f\,x\right )\,\left (a^2\,b+4\,a\,b^2+8\,b^3\right )}{2\,a^2}-\frac {\left (2\,a\,b^2-\frac {\mathrm {tan}\left (e+f\,x\right )\,\left (16\,a^5\,b^2+32\,a^4\,b^3\right )\,\left (a+2\,b\right )\,\sqrt {-b\,\left (a+b\right )}}{8\,a^2\,\left (a^3\,b+a^2\,b^2\right )}\right )\,\left (a+2\,b\right )\,\sqrt {-b\,\left (a+b\right )}}{4\,\left (a^3\,b+a^2\,b^2\right )}\right )\,\left (a+2\,b\right )\,\sqrt {-b\,\left (a+b\right )}\,1{}\mathrm {i}}{4\,\left (a^3\,b+a^2\,b^2\right )}+\frac {\left (\frac {\mathrm {tan}\left (e+f\,x\right )\,\left (a^2\,b+4\,a\,b^2+8\,b^3\right )}{2\,a^2}+\frac {\left (2\,a\,b^2+\frac {\mathrm {tan}\left (e+f\,x\right )\,\left (16\,a^5\,b^2+32\,a^4\,b^3\right )\,\left (a+2\,b\right )\,\sqrt {-b\,\left (a+b\right )}}{8\,a^2\,\left (a^3\,b+a^2\,b^2\right )}\right )\,\left (a+2\,b\right )\,\sqrt {-b\,\left (a+b\right )}}{4\,\left (a^3\,b+a^2\,b^2\right )}\right )\,\left (a+2\,b\right )\,\sqrt {-b\,\left (a+b\right )}\,1{}\mathrm {i}}{4\,\left (a^3\,b+a^2\,b^2\right )}}{\frac {b^2+\frac {a\,b}{2}}{a^3}-\frac {\left (\frac {\mathrm {tan}\left (e+f\,x\right )\,\left (a^2\,b+4\,a\,b^2+8\,b^3\right )}{2\,a^2}-\frac {\left (2\,a\,b^2-\frac {\mathrm {tan}\left (e+f\,x\right )\,\left (16\,a^5\,b^2+32\,a^4\,b^3\right )\,\left (a+2\,b\right )\,\sqrt {-b\,\left (a+b\right )}}{8\,a^2\,\left (a^3\,b+a^2\,b^2\right )}\right )\,\left (a+2\,b\right )\,\sqrt {-b\,\left (a+b\right )}}{4\,\left (a^3\,b+a^2\,b^2\right )}\right )\,\left (a+2\,b\right )\,\sqrt {-b\,\left (a+b\right )}}{4\,\left (a^3\,b+a^2\,b^2\right )}+\frac {\left (\frac {\mathrm {tan}\left (e+f\,x\right )\,\left (a^2\,b+4\,a\,b^2+8\,b^3\right )}{2\,a^2}+\frac {\left (2\,a\,b^2+\frac {\mathrm {tan}\left (e+f\,x\right )\,\left (16\,a^5\,b^2+32\,a^4\,b^3\right )\,\left (a+2\,b\right )\,\sqrt {-b\,\left (a+b\right )}}{8\,a^2\,\left (a^3\,b+a^2\,b^2\right )}\right )\,\left (a+2\,b\right )\,\sqrt {-b\,\left (a+b\right )}}{4\,\left (a^3\,b+a^2\,b^2\right )}\right )\,\left (a+2\,b\right )\,\sqrt {-b\,\left (a+b\right )}}{4\,\left (a^3\,b+a^2\,b^2\right )}}\right )\,\left (a+2\,b\right )\,\sqrt {-b\,\left (a+b\right )}\,1{}\mathrm {i}}{2\,f\,\left (a^3\,b+a^2\,b^2\right )} \]
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